The sum of squares of numbers is: 13Step-by-step explanation:Let x and y be two numbersThen,Difference of the squares of the numbers will be:[tex]x^2-y^2[/tex]Product will be: [tex]xy[/tex]Given identity is:[tex](x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2[/tex]Given values are: Difference of the squares of the numbers=[tex]x^2-y^2=5[/tex]Product of numbers = xy = 6Putting the values in the identity[tex](x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169[/tex]As we have to only find x^2+y^2Taking square root on both sides[tex]\sqrt{(x^2+y^2)^2}=\sqrt{169}\\x^2+y^2=13[/tex]The sum of squares of numbers is: 13Keywords: IdentitiesLearn more about identities at:brainly.com/question/8902155brainly.com/question/8955867#LearnwithBrainly