MATH SOLVE

3 months ago

Q:
# Between 10 pm and 7:45 am the water level in a swimming pool decreased by 13/16 inch. Assuming the constant rate how much did it drop each hour

Accepted Solution

A:

Answer: [tex]\frac{1}{12} [/tex] inches per hour .Step-by-step explanation:Between 10 pm and 7:45 am there are 9 hours and 45 minutes i.e. [tex]9+\frac{45}{60} =\frac{39}{4}[/tex] hours The water level in a swimming pool decreased by amount in [tex]\frac{39}{4}[/tex] hours = [tex]\frac{13}{16}[/tex] inches The water level in a swimming pool decreased by amount in 1 hour: = [tex]\frac{\frac{13}{16}}{\frac{39}{4}}[/tex] inches = [tex]\frac{13}{16} \times \frac{4}{39}[/tex] inches = [tex]\frac{1}{4} \times \frac{1}{3}[/tex] inches = [tex]\frac{1}{12} [/tex] inches Hence it drop by [tex]\frac{1}{12} [/tex] inches each hour .